2.48x^2-21.08x-11.16=0

Solution for 2.48x^2-21.08x-11.16=0 equation:

2.48x^2-21.08x-11.16=0

a = 2.48; b = -21.08; c = -11.16;
Δ = b2-4ac
Δ = -21.082-4·2.48·(-11.16)
Δ = 555.0736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21.08)-\sqrt{555.0736}}{2*2.48}=\frac{21.08-\sqrt{555.0736}}{4.96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21.08)+\sqrt{555.0736}}{2*2.48}=\frac{21.08+\sqrt{555.0736}}{4.96}
$